2x^2+2x-4=-4x^2-29x+26

Solution for 2x^2+2x-4=-4x^2-29x+26 equation:

2x^2+2x-4=-4x^2-29x+26

We move all terms to the left:

2x^2+2x-4-(-4x^2-29x+26)=0

We get rid of parentheses

2x^2+4x^2+29x+2x-26-4=0

We add all the numbers together, and all the variables

6x^2+31x-30=0

a = 6; b = 31; c = -30;
Δ = b2-4ac
Δ = 312-4·6·(-30)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-41}{2*6}=\frac{-72}{12}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+41}{2*6}=\frac{10}{12}
=5/6
$